Project Euler #16: Power digit sum

Question

2¹⁵ = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 2¹⁰⁰⁰?

Answer : 1366

Hacker Rank Problem

Solution:

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import java.util.*; import java.math.BigInteger; public class Solution { public static void main(String gg[]) { Scanner scanner=new Scanner(System.in); int numberOfTestCases=scanner.nextInt(); int number=0; long sum=0; while(numberOfTestCases!=0) { sum=0; number=scanner.nextInt(); BigInteger bb=new BigInteger("2"); bb=bb.pow(number); String s=bb.toString(); char c[]=s.toCharArray(); for(char cc:c) { sum+=(((int)cc)-48); } System.out.println(sum); --numberOfTestCases; } } }