Project Euler #30: Digit Nth powers
Question
Answer : 443839
Hacker Rank Problem
Solution
Surprisingly there are only three numbers that can be written as the sum of fourth powers of their digits:
Find the sum of all the numbers that can be written as the sum of fifth powers of their digits.
1634 = 14 + 64 + 34 + 44
8208 = 84 + 24 + 04 + 84
9474 = 94 + 44 + 74 + 44
As 1 = 14 is not a sum it is not included.
The sum of these numbers is 1634 + 8208 + 9474 = 19316.Find the sum of all the numbers that can be written as the sum of fifth powers of their digits.
Answer : 443839
Hacker Rank Problem
Solution
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | import java.util.*; public class Solution { public static void main(String[] args) { int n=new Scanner(System.in).nextInt(); long sum=0; for(long i=(long)Math.pow(10,0);i<=(long)2*Math.pow(10,n);i++) { String ok=""+i; int add=0; for(int j=0;j<ok.length();j++) { add+=(long)Math.pow(Integer.valueOf(""+ok.charAt(j)),n); } if(add==i &&i!=1) { sum+=i; } } System.out.println(sum); } } |
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