Project Euler #35: Circular primes
Question
Answer : 55
Hacker Rank Problem
Solution
The number, 197, is called a circular prime because all rotations of the digits: 197, 971, and 719, are themselves prime.
There are thirteen such primes below 100: 2, 3, 5, 7, 11, 13, 17, 31, 37, 71, 73, 79, and 97.
How many circular primes are there below one million?
There are thirteen such primes below 100: 2, 3, 5, 7, 11, 13, 17, 31, 37, 71, 73, 79, and 97.
How many circular primes are there below one million?
Answer : 55
Hacker Rank Problem
Solution
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 | import java.util.*; public class Solution { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); long res = 0; for(int i=2;i<n;i++) { if(isPrime(i)) { if(isCircularPrime(i)) res+=i; } } System.out.println(res); } public static boolean isCircularPrime(int n) { String s = String.valueOf(n); char[] arr = s.toCharArray(); int rotation = 0; while(rotation<s.length()) { arr = getNextRotation(arr); if(!isPrime(Long.valueOf(new String(arr)))) return false; rotation+=1; } return true; } public static char[] getNextRotation(char[] arr) { if(arr.length>1) { char temp = arr[0]; for(int i=0;i<arr.length-1;i++) { arr[i] = arr[i+1]; } arr[arr.length-1] = temp; } return arr; } public static boolean isPrime(long num) { try { if ( num > 2 && num%2 == 0 ) return false; int top = (int)Math.sqrt(num) + 1; for(int i = 3; i < top; i+=2) { if(num % i == 0) { return false; } } return true; } catch(Exception e) { throw e; } } } |
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